c++ - How many bits in the mantissa if I declare all floats as long doubles ?
- Nicholas Jordan (8/8) Jun 18 2006 The source code for an entrophy testing method I am trying to incorporat...
- Walter Bright (2/13) Jun 18 2006 long doubles have a 64 bit mantissa, a 15 bit exponent, and a 1 bit sign...
- Scott Michel (2/19) Jun 19 2006 I'd really like to see a SEF float format with two or more sign bits. :-...
The source code for an entrophy testing method I am trying to incorporate in my program has the comment: /* Bytes used as Monte Carlo co-ordinates. This should be no more bits than the mantissa of your "double" floating point type. */ #define MONTEN 6 I cannot determine from either the .asm or the .h or the help files how many bits are in the mantissa.
Jun 18 2006
Nicholas Jordan wrote:The source code for an entrophy testing method I am trying to incorporate in my program has the comment: /* Bytes used as Monte Carlo co-ordinates. This should be no more bits than the mantissa of your "double" floating point type. */ #define MONTEN 6 I cannot determine from either the .asm or the .h or the help files how many bits are in the mantissa.long doubles have a 64 bit mantissa, a 15 bit exponent, and a 1 bit sign.
Jun 18 2006
Walter Bright wrote:Nicholas Jordan wrote:I'd really like to see a SEF float format with two or more sign bits. :-)The source code for an entrophy testing method I am trying to incorporate in my program has the comment: /* Bytes used as Monte Carlo co-ordinates. This should be no more bits than the mantissa of your "double" floating point type. */ #define MONTEN 6 I cannot determine from either the .asm or the .h or the help files how many bits are in the mantissa.long doubles have a 64 bit mantissa, a 15 bit exponent, and a 1 bit sign.
Jun 19 2006